Hi
i have an Image in the database in the field {Foto}. Now i want to manipulate these with php (label it) and show this labeled version again in the form.
So i do a PHP Method “labelFoto” with two parameters, $foto and $text.
The PHP Method manipulate the $image and returns the manipulated $image.
But how can i display the manipulated Image now? I try to make a new field “LabeledFoto” with datatype image(Database) or image(File) and call the PHP Method like this:
{LabeledFoto} = labelFoto({Foto},“My Label”);
in the onload section of the form. But when i generate, i get an error, that the multiupload section not configured correctly and the LabeledFoto Field is not show.
Thank’s for your help and have a nice Weekend.
Steve